Question

Verify the identity (a + b )3 = a3 + 3a2b + 3ab2 + b3

Answer 1

See the attach file for ur ans

Answer 2

Answer:

(a+b)³=a³+3ab+3ab²+b³

Step-by-step explanation:

$LHS=(a+b)^{3}$

=$(a+b)(a+b)^{2}$

=$(a+b)(a^{2}+2ab+b^{2})$

/* By algebraic identity:

$\boxed {(x+y)^{2}=x^{2}+2xy+y^{2}}$*/

=$a(a^{2}+2ab+b^{2})+b(a^{2}+2ab+b^{2})$

= $a^{3}+2a^{2}b+ab^{2}+a^{2}b+2ab^{2}+b^{3}$

=$a^{3}+(2+1)a^{2}b+(1+2)ab^{2}+b^{3}$

= $a^{3}+3a^{2}b+3ab^{2}+b^{3}$

=$RHS$

Therefore,

(a+b)³=a³+3ab+3ab²+b³

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