Question

verify the identity a minus b whole square equal a square minus 2 a b + b square for a equal to 9 and b equal to 4​

Answer 1

Answer:

Given,

a = 9

b = 4

$(a-b)^{2}$  = $a^{2}$ + 2 ab + $b^{2}$

$(9 - 4)^{2} = 9^{2}$ -  2 x 9 x 4 + $4^{2}$

81 - 72 + 16

= 25

$(a-b)^{2}$

= a - b x a - b

= 9 - 4 x 9 - 4

= 5 x 5

= 25

∴ $(a-b)^{2}$ = $a^{2}$ -  2ab + $b^{2}$

Answer 2

Answer:

Here is your answer

Step-by-step explanation:

leave the strikeouts, just forgotten about the BODMAS theory.