Verify the law of conservation of mass for the following reaction:
N2 + 3H2 + 2NH
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Answer:
For the reaction N
2
(g)+3H
2
(g)⇌2NH
3
(g) in a vessel, after the addition of equal number of moles of N
2
and H
2
equilibrium state is achieved. Then [H
2
]<[N
2
].
Assume total volume is 1 L. So number of moles is equal to molar concentration.
Assume that 4 moles of N
2
and 4 moles of H
2
are mixed.
As per reaction stoichiometry, if 1 mole of N
2
will react with 3 moles of H
2
to reach equilibrium, then
4−1=3 moles of N
2
and 4−3=1 mole of H
2
will remain unreacted. Hence, [H
2
]<[N
2
].
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