Science, asked by pintupaswanramlakhan, 1 month ago

Verify the law of conservation of mass for the following reaction:
N2 + 3H2 + 2NH
Aiheen​

Answers

Answered by rajputswapneel
2

Answer:

For the reaction N

2

(g)+3H

2

(g)⇌2NH

3

(g) in a vessel, after the addition of equal number of moles of N

2

and H

2

equilibrium state is achieved. Then [H

2

]<[N

2

].

Assume total volume is 1 L. So number of moles is equal to molar concentration.

Assume that 4 moles of N

2

and 4 moles of H

2

are mixed.

As per reaction stoichiometry, if 1 mole of N

2

will react with 3 moles of H

2

to reach equilibrium, then

4−1=3 moles of N

2

and 4−3=1 mole of H

2

will remain unreacted. Hence, [H

2

]<[N

2

].

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