verify the mean value theorem for the integral for the function f(x)= x^3 on (0,1)
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Answer:
1/√3
Step-by-step explanation:
Given
verify the mean value theorem for the integral for the function f(x)= x^3 on (0,1)
ANSWER
We know that the mean value theorem says that there is at least one number c on (0, 1) such that f’(c) = 1, now f’(x) = 1.
The rate of change from x = 0 to x = 1 is f(1) – f(0) / 1 – 0 = 1/1 = 1
Now f(x) = x^3
f’(x) = 3 x^2 = 1
x^2 = 1/3
x = 1/√3
So c = 1/√3 = 0.57 which is within the interval (0,1)
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