Math, asked by pranavkumaresan3, 11 months ago

Verify the property ax(b+c)=(axb)+(axc) by taking:
a=-2, b=(9/5), c=(-2/15)

Answers

Answered by olamideolajuyi19
0

Answer:

1

Step-by-step explanation:

ax(b+c)=(axb)+(axc)

-2x(⁹/₅ - ²/₁₅) = (-2(⁹/₅)x)+(-2(- ²/₁₅)x)

(-¹⁸/₅ + ⁴/₁₅)x = (-¹⁸/₅)x + (⁴/₁₅)x

(-⁵⁴/₁₅ + ⁴/₁₅)x = (-⁵⁴/₁₅ + ⁴/₁₅)x

(-⁵⁰/₁₅)x = (-⁵⁰/₁₅)x

Therefore x = 1

Check : ax(b+c)=(axb)+(axc)

-2(1)(⁹/₅ - ²/₁₅) = (-2(1)(⁹/₅))+(-2(1)(-²/₁₅))

(-¹⁸/₅ + ⁴/₁₅) = (-¹⁸/₅)x + (⁴/₁₅)

(-⁵⁴/₁₅ + ⁴/₁₅) = (-⁵⁴/₁₅ + ⁴/₁₅)

(-⁵⁰/₁₅) = (-⁵⁰/₁₅)

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