Question

verify the property x(y+z) when x=–12/5, y=–15/4, z=8/3 I'll mark the correct answwr as branliest.... plz ans it in L H S and R H S method....

Answer 1

$x = \frac{ - 12}{5} \\ y = \frac{ - 15}{4} \\ z = \frac{8}{3} \\ x(y + z) = xy + xz \\ \frac{ - 12}{5} ( \frac{ - 15}{4} + \frac{8}{3} ) = \frac{ - 12}{5} (\frac{ - 15}{4} ) + ( \frac{ - 12}{5} ) \frac{8}{3 } \\ \frac{ - 12}{5} ( \frac{ - 45 + 32}{12} ) = \frac{180}{20} - \frac{96}{15} \\ \frac{ - 12}{5} ( \frac{ - 13}{12} ) = \frac{270 - 192}{30} \\ \frac{156}{60} = \frac{78}{30} \\ \frac{78}{30} = \frac{78}{30}$

Answer 2

Answer:

x=

5

−12

y=

4

−15

z=

3

8

x(y+z)=xy+xz

5

−12

(

4

−15

+

3

8

)=

5

−12

(

4

−15

)+(

5

−12

)

3

8

5

−12

(

12

−45+32

)=

20

180

−

15

96

5

−12

(

12

−13

)=

30

270−192

60

156

=

30

78

30

78

=

30

78