verify the rule n(AuB) +n(AnB) = n (A)+n(B) for A{1,2,3,5,7,9,11,13}and for B {1,2,4,6,8,12,13} who will give this answer with explanation I will make that person branlist...
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Answer:
n(A∪B)=n(A)+n(B)−n(A∩B)−−−−−−−(1)
Given n(A)=7
n(B)=9
n(A∪B)=14
Substituting in 1
14=7+9−n(A∩B)
⇒n(A∩B)=16−14=2
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If A={2,3,4,5} and B={0,1,2,3,6} then verify n(AB) = n(A) + n(B) − n(A∩B)
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