Question

verify whether 1 is the root of quadratic equation x²-2x+1=0​

Answer 1

Answer:

Equal roots = 1

Step-by-step explanation:

Given a quadratic equation such that,

{x}^{2} - 2x + 1 = 0x

2

−2x+1=0

To find the roots.

We need to first factorise it.

We will use the middle term splitting method.

Therefore, we will get,

= > {x}^{2} - x - x + 1 = 0=>x

2

−x−x+1=0

Taking out common terms, we have,

\begin{gathered} = > x(x - 1) - 1 (x - 1) = 0 \\ \\ = > (x - 1)(x - 1) = 0 \\ \\ = > {(x - 1)}^{2} = 0 \\ \\ = > x - 1 = 0 \\ \\ = > x = 1\end{gathered}

=>x(x−1)−1(x−1)=0

=>(x−1)(x−1)=0

=>(x−1)

2

=0

=>x−1=0

=>x=1

Clearly, it has equal and same roots.

Hence, the required root will be 1.

Answer 2

Step-by-step explanation:

• a=1,b=2,c=1
• d=b^2-4ac
• 2^2-4×1×1
• 4-4
• 0
• Yes 1 is the root of quadratic equation.
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