Question

Verify whether 2, 3 and 1/2 are the zeroes of the polynomial (p(x) = 2x^3 - 11x^2 + 17x - 6.

Answer 1

Answer:

Step-by-step explanation:

Please see the attachment below.

Hope it helps.

Answer 2

It is verified 2, 3 and 1/2 are the zeroes of the polynomial.

Step-by-step explanation:

Given : Polynomial $p(x) = 2x^3 - 11x^2 + 17x - 6$

To find : Verify whether 2, 3 and 1/2 are the zeroes of the polynomial ?

Solution :

Substitute the value of zeros in polynomial if it equate to zero then it is verified.

Put x=2,

$p(2) = 2(2)^3 - 11(2)^2 + 17(2) - 6$

$p(2) =16 - 44+34- 6$

$p(2) =0$

Put x=3,

$p(3) = 2(3)^3 - 11(3)^2 + 17(3) - 6$

$p(3) =54-99+51- 6$

$p(3) =0$

Put $x=\frac{1}{2}$,

$p(\frac{1}{2}) = 2(\frac{1}{2})^3 - 11(\frac{1}{2})^2 + 17(\frac{1}{2}) - 6$

$p(\frac{1}{2}) =\frac{1}{4}-\frac{11}{4}+\frac{17}{2}- 6$

$p(\frac{1}{2}) =0$

#Learn more

If 2 and -1/3 are the zeroes of polynomial 3x^3-2x^2-7x-3, find the third zero of the polynomial

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