Question

Verify whether 2, 3 and 1/3 are the zeroes of the polynomial p(x) = 2x^3- 11x^2 + 17x-6.​

Answer 1

Step-by-step explanation:

if x = 2

p(x) = 2x³-11x²+17x-6

p(2)= 2(2)³-11(2)²+17(2)-6

= 16- 44+34-6

= 0

if x= 3

p(x) =2x³-11x²+17x-6

p(3)= 2(3)³-11(3)²+17(3)-6

= 54-99+51 -6

= 0

if x= 1/3

p(x)=2x³-11x²+17x-6

p(1/3)= 2(1/3)³-11(1/3)²+17(1/3)-6

= 2/27-11/9+17/3-6

= 2-33+153-162/27

= -40/27is not equal to zero

Answer 2

here is your answer.I have done it thourghly.so you can understand that problem easily