Question

Verify whether 5 and 2 are the zeroes of the polynomial 2x2 -5x​

Answer 1

Step-by-step explanation:

Polynomial p(x) = 2x^3 - 11x^2 + 17x - 6p(x)=2x

3

−11x

2

+17x−6

To find : Verify whether 2, 3 and 1/2 are the zeroes of the polynomial ?

Solution :

Substitute the value of zeros in polynomial if it equate to zero then it is verified.

Put x=2,

p(2) = 2(2)^3 - 11(2)^2 + 17(2) - 6p(2)=2(2)

3

−11(2)

2

+17(2)−6

p(2) =16 - 44+34- 6p(2)=16−44+34−6

p(2) =0p(2)=0

Put x=3,

p(3) = 2(3)^3 - 11(3)^2 + 17(3) - 6p(3)=2(3)

3

−11(3)

2

+17(3)−6

p(3) =54-99+51- 6p(3)=54−99+51−6

p(3) =0p(3)=0

Put x=\frac{1}{2}x=

2

1

,

p(\frac{1}{2}) = 2(\frac{1}{2})^3 - 11(\frac{1}{2})^2 + 17(\frac{1}{2}) - 6p(

2

1

)=2(

2

1

)

3

−11(

2

1

)

2

+17(

2

1

)−6

p(\frac{1}{2}) =\frac{1}{4}-\frac{11}{4}+\frac{17}{2}- 6p(

2

1

)=

4

1

−

4

11

+

2

17

−6

p(\frac{1}{2}) =0p(

2

1

)=0

Answer 2

Given

Polinomial=2x²-5x

To Find

• Zero's of the polynomial

Solution

☞2x²-5x=0

☞2x²=5x

☞x²=$\frac{5x}{2}$

☞x=$\sqrt{\frac{5x}{2} }$

Hope it helps you...