Question

Verify whether g(x) is a factor of p(x) using factor theorum

p(x)= x^3 - 3ax^2 + 3a^2x - a^3 and g(x) = x-a

Answer 1

Answer:

$x - a = 0 \\ x = a \\ \\ p(a) = {a}^{3} - 3 {a}^{3} + 3{a}^{3} - {a}^{3} \\ = 0 \\ 0 = 0 \\ \\ hence \: g(x) \: is \: the \: factor \: of \: \\ p(x)$

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