verify whether the following are
zeroes of the polynomial indicated against them
p(x) = (x + 1) (x-2), at x=-1 ,2
Answers
Answered by
2
Step-by-step explanation:
putting the values in x
-1+1)(-1-2)
0(-3)
0 no
(2+1)(2-2)
3(0)
0 hence no one is the zero of the polynomial
Answered by
2
Step-by-step explanation:
P(x)=(x + 1) (x-2)
p(x)=x^2+1-2
put x=1
p(1)=1-1
p(1)=0
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