verify whether the line x-3/-4 = y-4/-7= z+3/12 lies in the plane 5x-y+z=8
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dkjdhsoanbzhsis wojq
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Step-by-step explanation:
for a given line to lie on a plane ,it must be perpendicular to the normal vector to the plane.
vector b = -4i-7j+12k and normal vector n = 5i-j+k
if line lie on a plane the dot product of vector b and normal vector n must be zero
b.n = ( -4i-7j+12k).(5i-j+k)
= -20+7+12
= -1 0
hence our line does not lie on a plane
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