verify whether the value of x given in each case are the zeroes of polynomial or not
1.p(x)=2x+1;x=-1/2
2.p(x)=5x- pie ;x=-3/2
3.p(x)=xsq -1;x=+1
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Answer:
◇ p(x) = 2 (-1/2) + 1
g(x) = -1/2
-1 + 1 = 0
0 = 0
hence the -1/2 is zero of p(x)
◇ p(x)=5x-pie
g(x)=-3/2
5(-3/2) - 22/7 =0
-15/2 - 22/7 =0
3.14 - 3.14 =0
0=0
◇p(x)= x^2 - 1
g(x)= 1
(1)^2 -1 =0
1-1 =0
0=0
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