Question

verify whether the values of x given in each case are the zeroes of the polynomial or not 1.p(x)=(x-1)(x+2); x=-1,-2​

Answer 1

Answer:

Step-by-step explanation:

P(x) = (x - 1)(x + 2)

⇒ x = -1

P(-1) = (-1 - 1)(-1 + 2)

= (-2)(1)

= -2

-2 ≠ 0

⇒x = -2

P(-2) = (-2 - 1)(-2 + 2)

= (-3)(0)

= 0

∴ x = -1 is not the correct value

but x = -2 is the correct value.

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