Question

verify whether x = 3,-7 are the zeroes of p(x)=(x+3)(x-7) or not

Answer 1

$p(3) = (3 + 3)(3 - 7) = 6 \times - 4 \\ = - 24 \\ p( - 7) = ( - 7 + 3)( - 7 - 7) \\ = - 4 \times - 14 \\ = 56 \\ p(3) \: and \: p( - 7) \: are \: \: not \: equal \: to \: zero \\ hence \: 3 \: and \: - 7 \: are \: \: not \: roots \: of \: p(x)$

Answer 2

No since(x+3)(x_7)=0
x=_3 orx=7