Verify : x^3+y^3=(x+y)(x^2-xy+y^2)
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Answer:
R.H.S => (x+y) ( x2 - xy + y2)
=> x3 - x2y + xy2 + x2y - xy2 + y3
{On multiplying x3 + y3 with (x+y) ( x2 - xy + y2)}
=> [x3 + y3] + ( -x2y + x2y) + ( xy2 - xy2)
=> x3 + y3
Since R.H.S = L.H.S,
That is x3 + y3 = x3 + y3
Hence, verified that
Hence, verified that x3 + y3 = (x+y) ( x2 - xy + y2)
tq
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R.H.S= (x+y) ( x^2- xy +y^2)
=x^3 -x^2y+ xy^2 +x^2y - xy^2 + y^3
= x^3+y^3= R.H.S
=
Step-by-step explanation:
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