Question

verify x^3+y^3=(x+y)(x^2-xy+y^2)

Answer 1

x^3+y^3=(x+y)(x^2-xy+y^2)
x^3+y^3=x^3-x^2y+xy^2+x^2y-xy^2+y^3
x^3+y^3=x^3+y^3
I hope this helps you

Answer 2

Here's your answer!!

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$= > {x}^{3} + {y}^{3} =$


$(x + y)( {x}^{2} - xy + {y}^{2} )$


${x}^{3} - {x}^{2}y + x {y}^{2} + {x}^{2} y - xy^{2} + {y}^{3}$


$= > - {x}^{2}y \: and \: {x}^{2} get \: cancelled \\ = > x {y}^{2} \: and \: \: - x {y}^{2} \: get \: cancelled$

${x}^{3} + {y}^{3}$


$= > {x}^{3} + {y}^{3} = {x}^{3} + {y}^{3}$


=>LHS=RHS

Hence,it is proved !

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Hope it helps you!! :)