verify
(x+y)3=x3 + y3 + 3xy (x+y)
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Step-by-step explanation:
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Answered by
6
Step-by-step explanation:
=(x+y)^2
Now, Split the equation
=(x+y)(x+y)(x+y)
=(x+y)^2(x+y)
=(x^2+ y^2 +2xy)(x+y)
=x(x^2+ y^2 +2xy)+ y(x^2+ y^2 +2xy)
=x^3 +xy^2 +2x^2y+ x^2y+y^3 +2xy^2
=x^3 +y^3 +3xy^2+3x^2y
taking (x+y) common between 3xy^2+3x^2y
=x^3 + y^3 + 3xy(x+y)
Hence proved
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