verify |x+y| < |x| + |y|... if
x=-4/5,Y=2/5
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Answer:
x = - 4/5 and y = 2/5
|x + y| = |- 4/5 + 2/5|
=> |(- 4 + 2)/5|
=> |-2/5|
=> 2/5 LHS
=> |x| + |y|
=> |-4/5| + |2/5|
=> 4/5 + 2/5
=> 7/5 RHS
2/5 < 7/5
LHS < RHS
|x + y| < |x| + |y| Hence proved
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