Question

Verify:x+(y+z)=(x+y)+zbytakingx=−3/4,y=−3/8 and z=14/15

Answer 1

we have,

X = -3/4 , y = -3/8 , Z = 14/15

Now putting in above equation

-3/4 + (-3/8 +14/15) = (-3/4 + (-3/8)) + 14/15

Now you can solve it

Answer 2

$\huge \color{crimson} {\mid{\fbox{\cal{Answer}}\mid}}$

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$\cal \pink {\fbox {Given:-}}$

$➜{x=\frac {-3}{4}}$

$➜{y=\frac {-3}{8}}$

$➜{z=\frac {14}{15}}$

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$\cal \purple {\fbox {To\: verify:-}}$

$➜{x+(y+z)=(x+y)+z}$

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$\cal \orange {\fbox {By\: substituting\: given\: values:-}}$

$➜{\frac{-3}{4}}+(\frac{-3}{8}+\frac{14}{15})=(\frac{-3}{4}+\frac{-3}{8})+\frac{14}{15}$

$➜{\frac{-3}{4}}+(\frac{-3×(15)+14×(8)}{120})=(\frac{-3×(2)-3×(1)}{8})+\frac{14}{15}$

$➜{\frac{-3}{4}}+(\frac{-45+112}{120})=(\frac{-6-3}{8})+\frac{14}{15}$

$➜{\frac{-3}{4}}+\frac{67}{120}=\frac{-9}{8}+\frac{14}{15}$

$➜{\frac{-3×(30)+67×(1)}{120}}=\frac{-9×(15)+14×(8)}{120}$

$➜{\frac{-90+67}{120}}=\frac{-135+112}{120}$

$➜{\frac{-23}{120}}=\frac{-23}{120}$

$\cal \blue {L.H.S=R.H.S}$

$\cal \green {\fbox {Hence\: Verified//}}$

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$\color{cyan} {\mid{\fbox{\cal{Hope\: it\: works}}\mid}}$