Question

Verity that points P(-2, 2), Q(2, 2) and R(2.7) are vertices of a right angled
triangle.
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Answer 1

Step-by-step explanation:

PQ= √(x2-x1)²+(y2-y1)²

PQ=√(2+2)²+(2-2)²

PQ=√(4)²+0²

PQ=√16

PQ=4

QR=√(x3-x2)²+(y3-y2)²

QR=√(2-2)²+(7-2)²

QR=√0²+5²

QR=√25

QR=5

PR=√(x3-x1)²+(y3-y1)²

PR=√(2+2)²+(7-2)²

PR=√4²+5²

PR=√9²

PR=√81

PR=9

.°. PR²=PQ²+QR²

.°. PR²=4²+5²

.°. PR²=9²

°.° PR =9

.°. it's is proved the the points are vertices of a right angle triangle.