Question

vertical angle of an isosceles triangle is 80 degree . find its base angle

Answer 1

Let the base be x° and x°
Vertical angle of an isosceles triangle =80°
So,
( x + x + 80)° = 180°
2x + 80 = 180
2x = 180 - 80
2x = 100
X = 100/2
X = 50
So,its base angles are 50° and 50°
Hope it helps...!!!

Answer 2

Given:

Vertical angle=80°

To find:

The base angle

Solution:

The required measure of the base angle is 50°.

We know that the given triangle is isosceles and so the base angles will be equal.

Let the base angles be X degrees.

Now, the angles' sum=180°

By adding the angles, we get

Base angle+base angle+vertical angle=180°

X+X+80°=180°

2X=180°-80°

2X=100°

X=100°/2

X=50°

So, each angle is 50°.

Therefore, the required measure of the base angle is 50°.