Vertices of a triangle ABC are A(2,4),B(6,4),C(2,0) find the length of median AD *
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Here just do one thing,
as the median divides the base into two equal parts so
one would be 2×2^1/2 and one will be 4 now those two triangles have same areas but we have nothing to do with that
so let take one of the triangles and draw a median of it
now apply pythagoras theorem so
median of 1st triangle:
16=(2^1/2)^2 +h^2
so h=14^1/2 now
take second triangle and solve for the median by taking it as a hypotenuse
so (14^1/2)^2+(2^1/2)^2= square of your answer your answer!!!i.e square of the length of the median...
so , it would be 4
therefore the answer is4
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