vertices p and q of a square are on sides AB and AC of the triangle and verticesR and S are on side BC prove that side of square =72/17
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side of square is 72/17 cm
Step-by-step explanation:
missing information : BC=8cm, ar(∆ABC)=36cm²
Let draw AE ⊥ BC
Area of Δ ABC = (1/2) BC * AE
=> (1/2) 8 * AE = 36
=> AE = 9 cm
let say side of Square = x
AD/PQ = AE/EC
=> (9 - x)/x = 9/8
=> 72 - 8x = 9x
=> 17x = 72
=> x = 72/17
QED
Proved
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