Question

very much urgent ....


an electric refrigerator rated 400 watt operates 8 hours a day calculate the energy consumed per day in kilowatt hour​

Answer 1

P=400

KW=400/1000=0.4kW

T=8*30=240 hours.

electrical energy=P*t=0.4*240=96kWh

thus, electrical energy consumed by the refrigerator for 30 days is 96kWh

cost of 96kWh=96*3=288

HOPE THIS HELP U

IF NICE MARK BRAINLIEST

Answer 2

P=400 W = 0.4KW

Time(t) for which it is operated =8hrs

As we know energy = power x time

E=Pt

E= 0.4(8)

E=3.2 KWH(kilowatt per hr)

Hence energy consumed is 3.2 KW PER HOUR.

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