Question

Very Short Answer Type Questions
(1 mark each
6. Find the number nearest to 110000 but greater than 100000 which is exactly
divisible by cach of 8.15 and 21.​

Answer 1

.

$190200$

Now, 109200 is also greater than 100000. Thus, the number nearest to 110000 and greater than 100000 which is exactly divisible by 8, 15, and 21 is 109200.

Answer 2

Answer:

Now, 109200 is also greater than 100000. Thus, the number nearest to 110000 and greater than 100000 which is exactly divisible by 8, 15, and 21 is 109200