Question

VERY SIMPLE:
find x:
$\frac{1}{ax-1} + \frac{1}{bx-1}$=0

Answer 1

$\frac{1}{ax-1} + \frac{1}{bx-1}=0$

$\frac{(bx-1)+(ax-1) }{(ax-1)(bx-1)} = 0$

$ax-1 + bx-1 = 0$
$ax+bx-2=0$
$(a+b)x=2$

$x= \frac{2}{a+b}$

Answer 2

  1   +    1    = 0
ax-1    bx-1
taking L.C.M
(bx-1)+(ax-1)   =0
(ax-1)(bx-1) 
bx-1+ax-1=0            [0*(ax-1)(bx-1)=0]
bx+ax-2=0
bx+ax=2
taking x as common
x(b+a)=2
x=   2
   b+a