Question

very urgent please fast​

Answer 1

$\large\underline{\sf{Solution-}}$

Given number is

$\rm :\longmapsto\:\dfrac{1}{3} \times \dfrac{ - 4}{9}$

can be rewritten as

$\rm \:  =  \:  \: \dfrac{ - 4}{27}$

$\large\underline{\sf{Solution-1}}$

To find the multiplicative inverse,

Let we recall the definition of Multiplicative inverse,

Let x be any non zero real number, then by what number it should be multiplied to get 1, that number is called Multiplicative inverse of x.

Or in other words, if x is non - zero real number, then its multiplicative inverse is 1/x.

So, here given number is

$\rm :\longmapsto\:Number = - \dfrac{4}{27}$

Let its multiplicative inverse be x

So,

$\rm :\longmapsto\: - \dfrac{4}{27} \times x = 1$

$\bf\implies \:x = - \dfrac{27}{4}$

$\large\underline{\sf{Solution-2}}$

To find the Additive inverse,

Let we recall the definition of Additive inverse,

Let x be any real number, then what number should be added to x, to get 0, that number is called Additive inverse of x.

Or in other words, if x is any real number, then its additive inverse is - x.

So, here given number is

$\rm :\longmapsto\:Number = - \dfrac{4}{27}$

Let its additive inverse be x.

So,

$\rm :\longmapsto\: - \dfrac{4}{27} + x = 0$

$\bf\implies \: x = \dfrac{4}{27}$

Hence,

$\rm :\longmapsto\:Multiplicative \: inverse \: of \: \dfrac{1}{3} \times \dfrac{ - 4}{9} \: = \: - \: \dfrac{27}{4}$

and

$\rm :\longmapsto\:Additive \: inverse \: of \: \dfrac{1}{3} \times \dfrac{ - 4}{9} \: = \: \: \dfrac{4}{27}$