Very urgent plz help!
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sorry I do know
ru 10std
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Angles are :-
x-8° & 5x-4°.
We know that,
Sum of interior angle on same side of transversal = 180°
Therefore,
x-8 + 5x-4 = 180°
6x = 180-12
6x = 168°
x = 168/6
x = 28°
Therefore angels are:-
x - 8°
= 28-8
= 20°
5x -4
= 5 (28) -4
= 140-4
= 134°
Hope it helps.
x-8° & 5x-4°.
We know that,
Sum of interior angle on same side of transversal = 180°
Therefore,
x-8 + 5x-4 = 180°
6x = 180-12
6x = 168°
x = 168/6
x = 28°
Therefore angels are:-
x - 8°
= 28-8
= 20°
5x -4
= 5 (28) -4
= 140-4
= 134°
Hope it helps.
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