Question

Vessel a contains 35 litres of milk and vessel b contains 40 litres of water

Answer 1

Answer:

There are two vessels A and B. Vessel A is containing

40 litres of pure milk and vessel B is containing 22 litres of

pure water. From vessel A, 8 litres of milk is taken out and

poured into vessel B. Then 6 litres of mixture (milk and

water) is taken out and from vessel B poured into vessel A.

What is the ratio of the quantity of pure milk in vessel A to

the quantity of pure water in vessel B?

(a) 14 : 9

(b) 21 : 11

(c) 24 : 13

(d) 14 : 5

(e) 21 : 13

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Answer 2

Question:

There are two vessels A and B. Vessel A is containing 40 liters of pure milk and vessel B is containing 22 liters of pure water. From vessel A, 8 liters of milk is taken out and poured into vessel B. Then 6 liters of the mixture (milk and water) is taken out and from vessel, B poured into vessel A. What is the ratio of the quantity of pure milk in vessel A to the quantity of pure water in vessel B?

(a) 14 : 9

(b) 21 : 11

(c) 24 : 13

(d) 14 : 5

(e) 21 : 13

Answer: 21 : 11

Step-by-step explanation: Initial quantity of milk in vessel A = 40 L

The initial quantity of water in vessel 8 = 22 L

Now, 8 L of milk is poured into vessel B.

∴  Quantity of milk left in the vessel,

A=40-8 =32 L

∵ Quantity of milk in vessel B =8 L and quantity of water in vessel B =22 l

∴ (Milk : water ) in vessel

B =8 : 22 =4 : 11

Now, 6 L of the mixture (milk and water) is taken out from vessel B and poured into vessel A.

∴ Quantity of milk in 6 L

$= 6\times \frac{4}{5}\\= \frac{2\times4}{5}\\ =\frac{8}{5}$

and quantity of water in 6 L

$6\times\frac{11}{15} =\frac{2\times11}{5} =\frac{22}{5}$

Now, the quantity of milk in vessel A

$=32+\frac{8}{5} =\frac{168}{5}$

and quantity of water in vessel B

$=22-\frac{22}{5} =\frac{88}{5}$

∴ Required ratio $=\frac{168}{5} ; \frac{88}{5}$

= 168 : 88

= 21 : 11

Hence,  the ratio of the quantity of pure milk in vessel A to the quantity of pure water in vessel B is 21 : 11.

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