English, asked by divyadeep4, 10 months ago

(vi) 11x - [8y - {1 1x –(72-3y) + 5y – (3x – 2y – z)}]​

Answers

Answered by aditik786461
6

Answer:

19x+2y−6z

Explanation:

11x−[8y−{11x−(7z−3y)+5y−(3x−2y−z)}]

11x−[8y−{11x−7z+3y+5y−3x+2y+z}]

11x−[8y−11x+7z−3y−5y+3x−2y−z]

11x−[−8x−2y+6z]

11x+8x+2y−6z

19x+2y−6z

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