(vi) 3x2 - x -4 find the zero of polynominal
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Answered by
5
Answer:
3x²-x-4
3x²-(4x-3x)-4
3x²-4x+3x-4
x(3x-4)+1(3x-4)
(x+1)(3x-4)
Answered by
6
Answer:
Firstly, we can factorise this term by splitting the middle terms.
3x2 + x - 2
= 3x2 +3x - 2x -2
= 3x (x + 1) -2 (x + 1)
= (x + 1) (3x - 2)
Since we have two factors now, it means that the polynomial has two zeros. We know now that x would have such a value by substituting which we would get the answer as 0.
x + 1 = 0
=> x = 0 - 1 = -1
3x - 2 = 0
=> 3x = 0 + 2 = 2
=> x = 2/3
Therefore the zeros of the polynomial 3x2 + x - 2 are -1 and 2/3
Step-by-step explanation:
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