Question

(vi) Determine the electric potential at the midpoint of the line joining two charges 2 × 10^5C
and -1 × 10^5 C placed in vacuum 10 cm apart​

Answer 1

$\huge\mathcal{Answer࿐ }$

Let p be the point of zero potential be p at distance r from the charge 1..

d=16 cm

Electric potential, v=q1/4πϵor+q2/4πϵo(d−r)

for v=0,

rq1=−d−rq2

⇒r5×10−8=0.16−r−3×10−8

r=10 cm

If, point p is outside,

v=q1/4πϵor+q2/4πϵo(r−d)

so here, r=40 cm

Answer 2

Answer:

refer to attachment

Explanation:

hope helpful