(vi) For the reaction :
N204 → 2 NO2
(g) (8)
(AH°= +57.24 kJ, AS°= 175.8 Jk')
At what temperature the reaction will be spontaneous?
Answers
Answered by
7
Explanation:
we have
T=delta H÷ delta S
T=57.24×10^3÷175.8
T=325.59K
Similar questions