(vi) If ZEHG = 48°, ZHGO =
Answers
Answered by
1
Answer:
The graph of y=sinx can be drawn as shown in the diagram.
∴ Required area =Area OABO+Area BCDB
=∫
0
π
sin x dx+
∣
∣
∣
∣
∣
∫
π
2π
sin x dx
∣
∣
∣
∣
∣
=[−cosx]
0
π
+
∣
∣
∣
[−cosx]
π
2π
∣
∣
∣
=[−cosπ+cos 0]+∣−cos 2π+cos π∣
=1+1+∣(−1−1)∣
=2+∣−2∣
=2+2=4 sq. units
PLEASE FOLLOW ME
Similar questions