Math, asked by paswananil01404, 1 year ago

VI. Using identities, evaluate i)107×103​

Answers

Answered by Anonymous
2

\huge{\mathcal{\blue{\underline{Answer}}}}

 = 107 \times 103 \\  = (100 + 7)(100 + 3) \\  = (100) {}^{2}  + (7 + 3)10 0 + (7)(3) \\  = 10000 + 1000 + 21 \\

\huge{\mathcal{\blue{\underline{=11021}}}}

☑ Identity Used :

 = x {}^{2}  + (a + b)x + (a)(b)

Answered by generousgenius
0

Answer:

11021

107= 100+7

103=100+3

(100+7)(100+3)

(x+a)(x+b)=x^2+(a+b)x+ab

(100)^2+(7+3)100+7×3=11021

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