Question

(vi) y =e2 (a+bx)
ਕਹੈ​

Answer 1

Answer:

y = e2x (a + bx) …(1)

differentiating w.r.t x, we get

⇒ y1= e2x (0 + b) + (a + bx) e2x 2

⇒ y1 = e2xxb + (a + bx) e2x 2 ….(2)

putting (1) in (2),

y1 = be2x + 2y

⇒ y1 – 2y = b e2x ….(3)

again differentiating w.r.t x,

we get y2 – 2y1 = b.e2x.2 ….(4)

putting (3) in (4) we get

y2 – 2y1 = 2y1 – 4y

⇒ y2 – 4y1 + 4y = 0