Math, asked by neetamecwan, 9 months ago

Vidhi is 10 years elder than Tithi. Tithi
is 2 years younger than Swati but 1 year
elder than Ekta. Their ages add up to a
number which is a multiple of 3 between
121 to 125. Find the present age of each.​

Answers

Answered by Angelsonam
17

Answer:

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Answered by MaIeficent
28

Step-by-step explanation:

\bf{\underline{\underline\red{Given:-}}}

  • Vidhi is 10 years elder than Tithi.

  • Tithi is 2 years younger than Swathi but 1 years elder than Ekta.

  • Their ages add up to a number which is a multiple of 3 between 121 and 125.

\bf{\underline{\underline\blue{To\:Find:-}}}

  • The present ages of each of them.

\bf{\underline{\underline\green{Solution:-}}}

Let the present age of Tithi be x

Present age of Vidhi = x + 10

Present age of Swati = x + 2

Present age of Ekta = x - 1

Their ages add up to a number which is a multiple of 3 between 121 to 125.

The multiple of 3 between 121 ana 125 is 123

Therefore:-

\rm \implies(x) + (x + 10) + (x + 2) + (x - 1) = 123

\rm \implies x+ x + 10+ x + 2+ x - 1 = 123

\rm \implies 4x + 11 = 123

\rm \implies 4x= 123 - 11

\rm \implies 4x= 112

\rm \implies x=  \dfrac{112}{4}

\rm \implies x=  28

Hence:-

Present age of Tithi = x = 28 years

Present of Vidhya = x + 10 = 38 years

Present age of Swati = x + 2 = 30 years

Present age of Ekta = x - 1 = 27 years

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