Question

vigyapan on chocolate in hindi

Answer 1

Explanation:

We have to prove that the difference of two sides of a triangle is less than the third side.

Refer to the attached image.

To prove: AC-AB< BC

Construction: Mark a point 'D' on AC such that the distance AB=AD

Therefore, we have to prove that AC-AD<BC

So, we have to prove that CD < BC

Proof:

Consider triangle ABD,

since AB=AD

Since, opposite angles opposite to the equal opposite sides are always equal.

So, \angle ABD=\angle ADB∠ABD=∠ADB

So, p = p

Now, let \angle DBC=x , \angle BDC=y∠DBC=x,∠BDC=y

Now, using exterior angle property in triangle ABD,

Exterior angle property of a triangle states that the measure of an exterior angle is equal to the sum of the two interior angles.

y=p+\angle Ay=p+∠A (equation 1)

Now, using exterior angle property in triangle BCD,

p=x+\angle Cp=x+∠C

x=p-\angle Cx=p−∠C (equation 2)

Now, by comparing equation 1 and 2,

p+\angle A>p-\angle Cp+∠A>p−∠C

So, y > x

BC > CD

CD < BC

AC - AD < BC

Since, AD = AB

Therefore, AC - AB < BC

Hence, proved.

Answer 2

HERE IS YOUR ANSWER :-

सभके पसंद की चॉकलेट,

आ-गई अभ बाज़ार में,

जल्दी से भरने के लिए अपनी प्लेट,

लग जाओ सभ कतार में।

वह क्या स्वाद है,

क्या रंग है,

इस चॉकलेट क।

यम यम यम...................

बहुत मज़े की चॉकलेट,

तुम भी आओ,

जल्दी आओ,

खरीदलो अपनी पसंद की चॉकलेट।

HOPE IT HELPS...

FOLLOW ME...

MRK AS BRAINLIEST...