Question

(vii) 72 - [3 + {18 - 19 - 2}] = {1 + 5 of 7 - (3 - 1)}​

Answer 1

Answer:

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Answer 2

72 ≠ 2

Given: 72 - [3 + {18 - 19 - 2}] = {1 + 5 of 7 - (3 - 1)}

To Find: The solution of RHS and LHS

Solution: 72 - [3 + {18 - 19 - 2}] = {1 + 5 of 7 - (3 - 1)}

In the above equation, we need to solve the brackets to get the answer.

Solving LHS:

72 - [3 + {18 - 19 - 2}]

First, we will solve the innermost bracket:

72 - [3 + {- 3}] (Since 18 - 19 - 2 = -3)

Now, we will solve the outer bracket:

72 - [3 - 3}] (+ - = -)

72 - [0]

72 (LHS)

Solving RHS:

{1 + 5 of 7 - (3 - 1)}

First, we need to solve the inner bracket:

{1 + 5 of 7 - (2)} (Since 3 - 1 = 2)

{1 + 5 of 5} (Since 7 - 2 = 5)

Here, of means division

So, put the division sign:

{1 + 5 ÷ 5}

Using the BODMAS rule we will solve division first.

1 + 1 (Since 5 ÷ 5 = 1)

2 (RHS)

From LHS and RHS we get:

72 ≠ 2

LHS is not equal to RHS.

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