Math, asked by latatomer83, 1 month ago


(vii) p(x) = cx +d, c≠0, c, d are real numbers.​

Answers

Answered by sangeetakumari1r
4

Answer:

-d/c

Step-by-step explanation:

p(x)=cx+d=0

cx=0-d

cx=-d

x=-d/c

Answered by neetussharma
6

Answer: The zeroes of the polynomial are defined as ,  -d/c where c is not equal to 0 c, d are real numbers.

The given polynomial is p(x) = cx+d

Where,  c is not equal to 0 c, d are real numbers.

To find the zeroes of the given polynomial, equate the polynomial equal to 0.

p(x) =0

cx+d=0

Subtract d from both the sides.

cx= -d

Divide both sides by c.

x=-d/c

Therefore the zeroes of the polynomial are defined as , where c is not equal to 0 c, d are real numbers.

Step-by-step explanation:

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