(vii) Solution set of the inequation
2
−2
< 0 is :
(a) (−∞, 2) (b) (−∞, 2] (c) (2, ∞) (d) [2, ∞)
(viii) If( + 2)! = 462 ()! , then n is:
(a) 10 (b) 15 (c) 20 (d) none of these
(ix) If the third term of G.P. is 10 . Then the product of the first five terms of G.P. is :
(a) 1000 (b) 10000 (c) 100000 (d) none of these.
(x) If 2 + 1,
2 + + 1 3
2 − 3 + 3 are in A.P. , then the value(s) of x :
(a) 1 , 2 (b) -1 , -2 (c) 1 , -1 (d) none of these
(xi) The distance between the lines 9 + 40 − 20 = 0 9 + 40 + 21 = 0 ∶
(a) 1 (b) 41 (c) 49 (d) none of these
(xii) If the slope of the line joining (2,5) and (3, ) is -2 , then value of is :
(a) -3 (b) 3 (c) 2 (d) none of these.
(xiii) The centre of the circle ( + 5)
2 + ( − 3)
2 = 36 is :
(a) (-5,3 ) (b) (5,3 ) (c) ( 5,-3 ) (d) (-5,-3 )
(xiv) The eccentricity of parabola
2 = −16 is :
(a) 4 (b) 2 (c) 1 (d) none of these
(xv) The probability of not getting doublets in a single throw with pair of dice is :
(a) 25
36
(b) 6
36
(c) 1
36
(d) none of these
(xvi) The probability that a non leap year , selected at random will contain 53 Sunday is :
(a) 1
7
(b) 2
7
(c) 1 (d) none of these
2. (i) If A is any empty set and B is the set of vowels then ∩ is equal to A.
(ii) Conversion of 5
3
radians into degree is 330֯ .
(iii) If C (n, 8) = C (n,2) , then C(n,10) =1 .
(iv) The product of three G.M.s between 4 and 1
4
is 1.
(v) Slope of line y=7 is 7 .
(vi) Imaginary part of a complex number 4 + 5 is 4.
(vii)
2
16
+
2
9
=1 is equation of an ellipse.
Answers
Given : third term of G.P. is 10
slope of the line joining (2,5) and (3, y) is -2
To Find : product of the first five terms of G.P. is :
Value of y
The probability of not getting doublets in a single throw with pair of dice
The probability that a non leap year , selected at random will contain 53 Sunday
Solution:
third term of G.P. is 10
GP is a/r² , a/r , a , ar , ar²
a = 10
Product = a/r² × a/r × a × ar × ar² = a⁵ = 10⁵ = 100000
slope of the line joining (2,5) and (3, y) is -2
=> (y - 5)/(3 - 2) = - 2
=> y - 5 = - 2
=> y = - 2 + 5
=> y = 3
The probability of not getting doublets in a single throw with pair of dice
= 1 - 6/36
= 1 - 1/6
= 5/6
365 = 52 x 7 + 1
The probability that a non leap year , selected at random will contain 53 Sunday is 1/7
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