Question

viii) A particle moves along a circle of radius r with constant tangential
acceleration. If the velocity of the particle is v at the end of second revolution,
after the revolution has started, then the tangential acceleration is
a) V2/ 871
b) V2 / 66
c) V2 / 4
d) V/ 21tr

Answer 1

Answer:

Initial speed of the particle u=0

Final speed of the particle is v

Distance covered in 2 revolutions S=2(2πr)=4πr

Using v

2

−u

2

=2aS

where a is the tangential acceleration

∴ v

2

−0=2a(4πr)

⟹ a=

8πr

v

2