Question

viii) The capacitance of an ideal capacitor is 2uF. What is it's reactance if the frequency of the applied alternating emf is 1000Hz?​

Answer 1

Answer:

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Answer 2

Given:

The capacitance of an ideal capacitor is 2uF.

To find:

Reactance when applied alternating emf is 1000Hz?

Calculation:

Capacitive Reactance will be :

$\rm \: \chi_{C} = \dfrac{1}{ \omega \times C}$

$\rm \implies\: \chi_{C} = \dfrac{1}{ 2\pi f \times C}$

$\rm \implies\: \chi_{C} = \dfrac{1}{ 2\pi \times 1000 \times (2 \times {10}^{ - 6}) }$

$\rm \implies\: \chi_{C} = \dfrac{1}{ 4\pi \times {10}^{ - 3} }$

$\rm \implies\: \chi_{C} = \dfrac{1000}{ 4\pi }$

$\rm \implies\: \chi_{C} = 79.57 \: ohm$

So, capacitive reactance is 79.57 ohm.