Question

vijay has 50 paise ,25 paise and 10 paise coins in the ratio 4:7:11 amounting ₹ 485. Find the number of coins of each type respectively.​

Answer 1

Answer:

vijay has coins 50 paise, 25 paise& 10 paise in ratio 4:7:11 respectively.

→ Assume bag contain x coin.

So, 50 paise = 4x coin

25 pasie = 7x coin

10 paise = 11x coin

• 485 ₹ = 48500 paise

so ,

$(50 \times 4x) + (25 \times 7x) + (10 \times 11x) = 48500 \: paise \\ 200x + 175x + 110x = 48500 \\ 485x = 48500 \\ x = \frac{48500}{485} \\ x = 100 \: paise$

50 paise = 4x = 4x100 = 400

25 paise = 7x = 7×100 = 700

10 paise = 11x = 11×100 = 1100

Total coins = 400 + 700 + 1100 = 2200

Answer 2

Given : Vijay has 50 paise, 25 paise and 10 paise coins in the ratio 4: 7: 11 amounting 485.

To Find : the number of coins of each type respectively.

Solution:

50 paise, 25 paise and 10 paise coins  4x , 7x , 11x  respectively

Value of 50 paise coins  =  4x * 50 /100  = 2x

Value of 25 paise coins = 7x * 25/100  =  1.75x

Value of 10 paise coins  = 11x * 10/100  = 1.1x

Total Value = 2x + 1.75x + 1.1x

= 4.85x

4.85x = 485

=> x = 100

coins are  400 , 700 and 1100  

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