Math, asked by harikeshray0p3qg8u, 1 year ago

vijay is older than seema by 12 years. Four years ago,Vijay was four times as old as his sister .Find their present ages.

Answers

Answered by Anonymous
3

Answer:

{\boxed{\bold{Seema= 16}}}

{\boxed{\bold{Vijay = 28}}}

Step-by-step explanation:

Given:-

⇢ Vijay is older then his sister seema by 12 years. Four year ago, Vijay was four times as old as his sister.

Find:-

⇢ Find their present ages.

Calculations:-

Let x be age of Seema and x + 12 be age of Vijay.

Four years ago:-

\rm{Seema = x - 4}

\rm{Vijay = x + 12 - 4 =x + 8}

Finding seema's age:-

\rm{4(x - 4) = 4x - 15}

\rm{4x - 16 = x + 8}

\rm{4x - x = 8 + 8}

{\boxed{\bold{x = 16}}}

Therefore, we know that 16 is the age of seema using seema's age we can find the age present age of Vijay.

\rm{x + 12}

\rm{16 + 12}

{\boxed{\bold{28}}}

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Therefore, 28 is the present age of Vijay.

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