Question

Vijay is older then his sister seema by 12 years. Four year ago, Vijay was four times as old as his sister. Find their present ages​

Answer 1

Answer:

⇢ ${\boxed{\bold{Seema= 16}}}$

⇢ ${\boxed{\bold{Vijay = 28}}}$

Step-by-step explanation:

Given:-

⇢ Vijay is older then his sister seema by 12 years. Four year ago, Vijay was four times as old as his sister.

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Find:-

⇢ Find their present ages.

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Calculations :-

• Let x be age of Seema and x + 12 be age of Vijay.

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Four years ago:-

⇢ $\rm{Seema = x - 4}$

⇢ $\rm{Vijay = x + 12 - 4 = 8}$

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Finding seema's age:-

⇢ $\rm{2(x - 4) = x + 8}$

⇢ $\rm{2x - 8 = x + 8}$

⇢ $\rm{2x - x = 8 + 8}$

⇢ ${\boxed{\bold{x = 16}}}$

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Therefore, we know that 16 is the age of seema using seema's age we can find the age present age of Vijay.

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⇢ $\rm{x + 12}$

⇢ $\rm{16 + 12}$

⇢ ${\boxed{\bold{28}}}$

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Therefore, 28 is the present age of Vijay.

Answer 2

$\huge\bold{\purple{\fbox {\pink{\mathbb{ANSWER}}}}}$

⇢ ${\boxed{\boxed{\bold{Seema= 16}}}}$

⇢ ${\boxed{\boxed{\bold{Vijay = 28}}}}$

Step-by-step explanation:

⭐Given:-⭐

⇢ Vijay is older then his sister seema by 12 years. Four year ago, Vijay was four times as old as his sister.

ㅤ

⭐Find:-⭐

⇢ Find their present ages.

ㅤ

⭐Calculations:-⭐

Let x be age of Seema and x + 12 be age of Vijay.

⭐Four years ago:-⭐

⇢ $\rm{Seema = x - 4}$

⇢ $\rm{Vijay = x + 12 - 4 = 8}$

ㅤ

⭐Finding seema's age:-⭐

⇢ $\rm{2(x - 4) = x + 8}$

⇢ $\rm{2x - 8 = x + 8}$

⇢ $\rm{2x - x = 8 + 8}$

⇢ ${\boxed{\boxed{\bold{x = 16}}}}$

➡Therefore, we know that 16 is the age of seema using seema's age we can find the age present age of Vijay.

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⇢ $\rm{x + 12}x+12$

⇢ $\rm{16 + 12}$

⇢ ${\boxed{\boxed{\bold{28}}}}$

➡Therefore, 28 is the present age of Vijay.

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