Vikram borrow 20000 from a bank at 10% per annum simple interest in lent it to his friend when comes at the same rate but compounded annually find his gain after 2 half years
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3
The amount that accrued from the money that Vikram borrowed from the bank:
Simple interest formula:
A = P( 1 + rt)
A = amount accrued
P = Principle, original amount
r = % rate, in decimal
t = time in years.
Therefore the amount (A) that Vikram had to pay back to the bank after to half years ( which is 1 year) was:
A = 20000 ( 1 + 0.1×1)
A = 20000 × 1.1
A = $22000
Interest he has to pay; 22000 - 20000 = $2000
We can calculate the amount that Vikram will get after lending to his friend at compound interest at the same rate:
Compound interest formula:
A = P ( 1 + r/n)^nt
A = amount accrued
P = principle amount, the original amount
r = % rate in decimal
n = number of compoundings in a year
t = number of years
Note:
-we will calculate compoundings of both semiannual and annul - since that was not clear in your question.
-Two half years is 1 year, so t = 1
Annual compunding, n = 1
A = P ( 1 + r/n)^nt
A = 20000 ( 1 + 0.1/1)^1×1
A = 20000 × 1.1^1
A = 20000 × 1.1 = $22000
- Interest his friend will give him; 22000 -20000 = $2000
Semiannual compouding, n = 2
A = P ( 1 + r/n)^nt
A = 20000 ( 1 + 0.1/2)^2×1
A = 20000 × 1.05^2
A = 20000 × 1.1025 = $22050
- interest his friend will give him if compounded twice a year; 22050 - 20000 = $2050
⇒Therefore if he lent to his friend compounding annually the profit would be:
2000 - 2000 = 0 , no profit
⇒ Therefore if he lent to his friend compounding semiannually, twice a year, the profit would be; 2050 - 2000 = $50
Simple interest formula:
A = P( 1 + rt)
A = amount accrued
P = Principle, original amount
r = % rate, in decimal
t = time in years.
Therefore the amount (A) that Vikram had to pay back to the bank after to half years ( which is 1 year) was:
A = 20000 ( 1 + 0.1×1)
A = 20000 × 1.1
A = $22000
Interest he has to pay; 22000 - 20000 = $2000
We can calculate the amount that Vikram will get after lending to his friend at compound interest at the same rate:
Compound interest formula:
A = P ( 1 + r/n)^nt
A = amount accrued
P = principle amount, the original amount
r = % rate in decimal
n = number of compoundings in a year
t = number of years
Note:
-we will calculate compoundings of both semiannual and annul - since that was not clear in your question.
-Two half years is 1 year, so t = 1
Annual compunding, n = 1
A = P ( 1 + r/n)^nt
A = 20000 ( 1 + 0.1/1)^1×1
A = 20000 × 1.1^1
A = 20000 × 1.1 = $22000
- Interest his friend will give him; 22000 -20000 = $2000
Semiannual compouding, n = 2
A = P ( 1 + r/n)^nt
A = 20000 ( 1 + 0.1/2)^2×1
A = 20000 × 1.05^2
A = 20000 × 1.1025 = $22050
- interest his friend will give him if compounded twice a year; 22050 - 20000 = $2050
⇒Therefore if he lent to his friend compounding annually the profit would be:
2000 - 2000 = 0 , no profit
⇒ Therefore if he lent to his friend compounding semiannually, twice a year, the profit would be; 2050 - 2000 = $50
mysticd:
it is wrong , plz , check ., sir
Answered by
25
Therefore ,
Vikram gain the amount = ( 4 ) - ( 1 )
= 5410 - 5000
= Rs 410
I hope this helps you.
: )
Vikram gain the amount = ( 4 ) - ( 1 )
= 5410 - 5000
= Rs 410
I hope this helps you.
: )
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